Parametric Surfaces

Surfaces can also be defined parametrically. In particular, suppose each component of a vector-valued function is a function of two variables u and v:
r(u,v) = á f(u,v) ,g(u,v) ,h(u,v) ñ
(1)

Then the graph of r( u,v) over some region S in the uv-plane is a surface in R3, and r( u,v) is called a parameterization of that surface.

Equivalently, x = f(u,v) , y = g( u,v) , and z = h( u,v) for (u,v) in S defines a surface, and the variables u and v are often called the coordinates of the surface.

Given a parametric surface (1), we often desire to transform it into a level surface representation of the form U(x,y,z) = k. To do so, we often use the trigonometric identities, such as the Pythagorean identities
cos2( t) +sin2( t) = 1
1+tan2( t) = sec2( t)
1-2sin2(t) = cos( 2t)
cosh2( t) -sinh2( t) = 1
1+cot2( t) = csc2( t)
2cos2(t) -1 = cos( 2t)
Other identities that may occur include 2sin( t) cos(t) = sin( 2t) and ete-t = 1.       

EXAMPLE 1    Find a level surface representation of the surface parameterized by
r( u,v) = á cos( u) cosh(v) ,sin( u) cosh( v) ,sinh( v) ñ
Solution: Since x = cos( u) cosh( v) , y = sin( u) cosh( v) , and z = sinh( v), the identity cos2( u) +sin2( u) = 1 leads to
x2+y2
=
cos2( u) cosh2( v) +sin2( u) cosh2( v)
=
cosh2( v) [ cos2( u) +sin2( u) ]
=
cosh2( v)
As a result, the identity cosh2( v) -sinh2(v) = 1 leads to
x2+y2-z2 = cosh2( v) -sinh2( v) = 1
Thus, r( u,v) = á cos( u) cosh( v) ,sin( u) cosh( v) ,sinh(v) ñ is a parameterization of the level surface
x2+y2-z2 = 1
which we recognize as a hyperboloid in one sheet.

Graphic of Directional Derivative

       

A sphere of radius R centered at the origin is often parameterized in terms of longitude q and latitude j, which results in the parameterization
r( q,j) = á Rcos( j) cos( q) ,Rcos( j) sin(q) ,Rsin( j) ñ
(2)
where q in [ 0,2p] and j is in [-p/2,p/2] .

       

EXAMPLE 2    Show that (2) is a parameterization of the sphere of radius R centered at the origin.       

Solution: Since x = Rcos( j) cos( q) , y = Rcos( j) sin( q) and z = Rsin( j) , the identity cos2( q) +sin2( q) = 1 leads to
x2+y2
=
R2cos2( j) cos2( q) +R2cos2( j) sin2( q)
=
R2cos2( j) [ cos2( q) +sin2( q) ]
=
R2cos2( j)
Moreover, z2 = R2sin2( j) implies that
x2+y2+z2 = R2cos2( j) +R2sin2(j) = R2
which is the equation of the sphere of radius R centered at the origin.

       

However, cartographers and mathematicians have long used parameterizations of the sphere other than (2). For example, in 1599, the mapmaker Gerard Mercator constructed a projection of the earth's surface in which a straight line on a map corresponds to a fixed compass bearing on the earth's surface. To do so, he imagined that the sphere was inside of a cylinder with radius R.

This led to the Mercator parameterization of the sphere:

r( q,m) = á R sech( m) cos( q) ,R sech( m) sin( q) ,Rtanh( m) ñ
where the hyperbolic secant and tangent functions are defined
sech( m) =  1
cosh( m)
,       tanh( m) =  sinh( m)
cosh( m)
We will examine the Mercator parameterization more closely in the exercises.

  

Check your Reading: How would you define csch(t)?